From the calculations performed, the Kb of the reaction is 9.9 * 10^-10
What is Kb?
The term Kb refers to the base dissociation constant of a solution. We have the following information from the question;
pH of the solution = 8.60
concentration of p-toluidine = 0.016-M
Recall that pOH = 14 - pH
pOH = 14 - 8.60 = 5.4
[OH] = Antilog (-5.4) = 3.98 * 10^-6 M
We have to set up the ICE table;
CH3C6H4NH2(aq) + H2O(l) ⇄ CH3C6H4NH3^+(aq) + OH^-(aq)
I 0.016 0 0
C -x +x +x
E 0.016 - x 3.98 * 10^-6 3.98 * 10^-6
Hence;
Kb = [3.98 * 10^-6]^2/[0.016 - 3.98 * 10^-6]
Kb = 9.9 * 10^-10
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