Can ΔTSR and ΔQRS be proven congruent by SAS?
A) yes, because along with the given information on the diagram, SR ≅ RS by the reflexive property
B) yes, because a reflection will map ΔTSR onto ΔQRS
C) yes, because P appears to be the midpoint of SQ and TR
D) no, because not enough is information given to prove the triangles congruent by SAS
![Can ΔTSR and ΔQRS be proven congruent by SAS A yes because along with the given information on the diagram SR RS by the reflexive property B yes because a refle class=](https://us-static.z-dn.net/files/d7d/2ed7eb9179f0ad5b9b216199cedc02b7.png)