NO LINKS. Part 1: Complete the sequence
![NO LINKS Part 1 Complete the sequence class=](https://us-static.z-dn.net/files/d0a/3a504e5ba4f77a6300cd570058e49ded.jpg)
Answer:
a) (6, 6) and (7, 4)
b) [tex]t(n)=-2n+18[/tex]
c) see attached
Step-by-step explanation:
From inspection of the table, we can see that as n increases by 2, t(n) decreases by 4. Therefore, as this a directly proportional relationship, it is a linear function.
So as n increases by 1, t(n) will decrease by 2.
Therefore, the remaining two ordered pairs are:
(6, 6)
(7, 4)
We know that the function decreases by 2 each time n increases by 1, so the slope (gradient) of the linear function will be -2.
Using the point-slope formula: [tex]y-y_1=m(x-x_1)[/tex]
(where [tex]m[/tex] is the slope and [tex](x_1,y_1)[/tex] is a point on the line)
Given:
[tex]\implies y-16=-2(x-1)[/tex]
[tex]\implies y=-2x+18[/tex]
[tex]\implies t(n)=-2n+18[/tex]
Graphing
To find the y-intercept, substitute [tex]n=0[/tex] into the equation:
[tex]\implies t(0)=-2(0)+18=18[/tex]
Therefore, the y-intercept is (0, 18)
To find where the line crosses the x-axis, set the equation to zero and solve for n:
[tex]\implies -2n+18=0[/tex]
[tex]\implies 2n=18[/tex]
[tex]\implies n=9[/tex]
Therefore, the line crosses the x-axis at (9, 0)