Question

What is the volume of 0.200 mol of an ideal gas at 200. kpa and 400. k? use p v equals n r t. and r equals 8.314 startfraction l times kilopascals over moles time k endfraction.. 0.83 l 3.33 l 5.60 l 20.8 l

Answer 1

3.33 liter is the volume of 0.200 mole of an ideal gas at 200 kPa pressure and 400 K temperature.

What is ideal gas equation?

Ideal gas equation for gas will be written as:

PV = nRT, where

P = pressure of gas = 200 kPa

n = moles of gas = 0.2 mole

T = temperature of gas = 400K

R = universal gas constant = 8.314 L.Pa/K.mole

V = to find?

On putting all these values on the above equation, we calculate for V as:

V = (0.2×8.314×400) / 200 = 3.325 = 3.33 L

Hence, option (2) is correct i.e. 3.33 L.

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