What is the electrical force between q1 and q2? recall that k = 8.99 × 109 n•meters squared over coulombs squared.. 4.3 × 1010 n 3.5 × 1010 n –5.4 × 1010 n –5.8 × 1010 n

Respuesta :

The electrical force between q₁ and q₂ will be  5.82 × 10⁻¹⁹ N.The electrical force is directly propotional to the product of mass and inverse of the square of the distance between them.

What is electric force?

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The given data in the problem is;

The electrical force between q₁ and q₂=?

k is the constant = 8.99 × 109 Nm

q is the charge of electron=  - 1.609 × 10⁻¹⁹ C

q₂ is the charge of proton=1.609 × 10⁻¹⁹ C proton

The electrical force is directly propotional to the product of mass and inverse of the square of the distance between them.

[tex]\rm F_E = \frac{Kq_1q_2}{r^2} \\\\ F_E = \frac{8.99 \times 10^9 \times 1.6 \times 10^{-19} \times 1.6 \times 10^{-19} }{(2 \times 10^{-5}^2} \\\\ \rm F_E = \= 5.82 \times 10^{-19} \ N[/tex]

Hence the electrical force between q₁ and q₂ will be 5.82 × 10⁻¹⁹ N.

To learn more about the electric force refer to the link;

https://brainly.com/question/1076352

Answer:

The other guy is wrong, the correct answer is C. Edge 2022.

~Hope this helps! :)

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