Question

The chemical equation below shows the combustion of methane (ch4). ch4 2o2 right arrow. co2 2h2o the molar mass of oxygen gas (o2) is 32.00 g/mol. the molar mass of carbon dioxide (co2) is 44.01 g/mol. what mass of co2, in grams, will form when 8.94 g o2 completely react? 3.25 grams 6.15 grams 13.0 grams 53.0 grams

Answer 1

6.15 grams of carbon dioxide is form when 8.94 g of oxygen is completely react.

How we calculate mass from moles?

Mass of any substance will be calculated from moles as :

n = W/M, where

W = required mass

M = molar mass

Given combustion reaction is:

CH₄ + 2O₂ → CO₂ + 2H₂O

Given mass of O₂ = 8.94 g

Molar mass of O₂ = 32.00 g/mole

Moles of O₂ = 8.94 / 32 = 0.279 mole

From the stoichiometry of the reaction, it is clear that:

2 moles of O₂ = produce 1 mole of CO₂

0.279 moles of O₂ = produce 1/2×0.279 = 0.139 moles of CO₂

Molar mass of CO₂ = 44 g/mole

Required mass of CO₂ will be calculated as:

W = n × M

W = 0.139 × 44 = 6.15 grams

Hence, option (2) is correct i.e. 6.15 grams.

To know more about moles, visit the below link:

https://brainly.com/question/15374113

Answer 2

Answer:

Option 2/ B. 6.15 grams on edge.

Explanation:

S/o to the person above me, got it because of them.