Question

Nitrogen gas at 20. °c in a balloon has a volume of 3.0 l and pressure of 1.5 atm. if the temperature of the balloon is increased to 30. °c and the pressure to 2.5 atm, what is the new volume of the balloon? use the formula: p1v1 t1 = p2v2 t2 temperature conversion: °c 273 k

Answer 1

The new volume of the balloon which was initially 3 L is 1.86 L

Data obtained from the question

• Initial temperature  (T₁) = 20 °C = 20 + 273 = 293 K
• Initial volume (V₁) = 3 L
• Initial pressure (P₁) = 1.5 atm
• New temperature (T₂) = 30 °C = 30 + 273 = 303 K
• New pressure (P₂) = 2.5 atm

• New volume (V₂) =?

How to determine the new volume

The new volume of the balloon can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(1.5 × 3) / 293 = (2.5 × V₂) / 303

Cross multiply

293 × 2.5 × V₂ = 1.5 × 3 × 303

732.5 × V₂ = 1363.5

Divide both side by 732.5

V₂ = 1363.5 / 732.5

V₂ = 1.86 L

Learn more about gas laws:

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Answer 2

Answer:

1.9L !!!!!

Explanation: