Question

A 5.00 L sample of helium expands to 15.0 L, at which point the pressure is measured to be 0.720 atm. What was the original pressure of the gas

Answer 1

The original pressure of a gas that has 5.00 L of its sample expanded to 15.0 L, at which point the pressure is measured to be 0.720 atm is 2.16atm.

How to calculate pressure?

The pressure of a gas can be calculated using the Boyle's law equation as follows:

P1V1 = P2V2

Where;

• P1 = initial pressure
• P2 = final pressure
• V1 = initial volume
• V2 = initial volume

P1 × 5 = 15 × 0.720

5P1 = 10.8

P1 = 10.8 ÷ 5

P1 = 2.16atm

Therefore, the original pressure of a gas that has 5.00 L of its sample expanded to 15.0 L, at which point the pressure is measured to be 0.720 atm is 2.16atm.

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