The value of s after calculation will be s=-1
It is given that
startfraction 1 over 64 endfraction = 4 superscript 2 s minus 1 baseline times 16 superscript 2 s 2
So the mathematical form will be
[tex]\dfrac{1}{64} =4^{2s-1} \times 16^{2s+2}[/tex]
[tex]4^{-3} =4^{2s-1} \times 16^{2s+2}[/tex]
[tex]4^{-3} =4^{2s-1} \times 4^{2(2s+2)[/tex]
[tex]4^{-3} =4^{2s-1+2(2s+2)[/tex]
[tex]4^{-3} =4^{2s-1+2(2s+2)[/tex]
[tex]-3=2s-1+2(2s+2)[/tex]
[tex]-3=2s-1+4s+4[/tex]
[tex]-3=6s+3[/tex]
[tex]-6=6s[/tex]
[tex]s=-1[/tex]
Thus the value of s after calculation will be s=-1
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