Question

Find the equation of a line that passes through the point (3,4) and has a gradient of 13. Leave your answer in the form y=mx+c​

Answer 1

Answer:

$y=13x-35$

Step-by-step explanation:

Use the point-gradient form of a linear equation:  $y-y_1=m(x-x_1)$

(where $m$ is the gradient and $(x_1,y_1)$ is a point on the line)

Given:

• $m = 13$
• $(x_1,y_1)=(3,4)$

$\implies y-y_1=m(x-x_1)$

$\implies y-4=13(x-3)$

$\implies y-4=13x-39$

$\implies y=13x-35$

Answer 2

Answer:

$y=13x-35$

Step-by-step explanation:

$m=13$

$(x_{1},y_{1})=(3,4)$

$y-y1=m(x-x1)$

$y-4=13(x-3)$

$y-4=13x-39$

$y=13x-35$