Question

A meter stick with a mass of 0.65 kg is held perpendicular to a vertical wall by a cord of length d = 4.8 m attached to the end of the meter stick and also to the wall above the other end of the meter stick. (a) Determine the tension in the cord.

Answer 1

With the mass of the meter stick at 0.65 kg and the length of the cord at d = 4.8 m, The tension in the cord is mathematically given as

T=1.756

What is the tension in the cord.?

Question Parameters:

A meter stick with a mass of 0.65 kg

a cord of length d = 4.8 m

Generally, the moment at point A  is mathematically given as

mg(0.5)=$tcos\theta x(1)$

$Tcos\theta=0.35*9.81*0.5$

Where

$\theta=sin^{-1}(1/4.8)\\\\\theta=12.02$

Hence

$Tcos\theta$=0.35*9.81*0.5

Tcos(12.02)=0.35*9.81*0.5

T=1.756

In conclusion, the tension in the cord is

T=1.756

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