A factory produces 1,250,000 toys each year. the number of toys is expected to increase by about 150% per year. which model can be used to find the number of toys, n (in millions), being produced in t years? n = startfraction 2.5 (1.5) over t endfraction, t not-equals 0 n = 1.5 t squared 1.25 n = 1.5 t 1.25 n = 1.25 times 2.5 superscript t

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The model that can be used to find the number of toys is  1.25* (2.5) ⁿ.

What is meant by an increment of 150%?

An increment of 150% means an increment of 1.5 times of initial value.

Number of toys initially = 1,250,000 or 1.25 millions

Number of toys after a year = 1.25 + 1.25*1.5 = 1.25*(2.5)¹

Number of toys after two year =1.25 * 2.5+ 1.25*2.5*1.5 = 1.25*(2.5)²

Number of toys after three year = 1.25* (2.5)³

So, Number of toys after n year = 1.25* (2.5)

Therefore, the model that can be used to find the number of toys is  1.25* (2.5) ⁿ.

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Answer:

c

Step-by-step explanation:

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