Respuesta :

Answer:

D.  18,000(0.97)^x

First, let's look at everything we know from reading the question.

We know that y = the population

We know that x = the number of years

We know the population starts at 18,000

We know the population is decreasing at a rate of 3% each year

Since the population is decreasing by 3%, the population will be 0.97 times the previous population each year.

This is because 100 - 3 = 97

That means we can make part of the equation.

y = 18,000(0.97)

Now, do we do 0.97^x or 0.97x?

Well, if we did 0.97x, it would look something like this

If x = 2

0.97(2) = 1.94

That means that, by 2 years, the population would be increasing when it should be decreasing

Now let's try 0.97^x

if x = 2

0.97^2 = 0.9409

That makes sense because the population would be decreasing by a slightly larger amount each time.

So, our final equation is

D.  18,000(0.97)^x

Lets check

[tex]\\ \rm\longmapsto P(1-r)^t[/tex]

  • P=18000
  • r=0.03

[tex]\\ \rm\longmapsto P(1-0.03)^t[/tex]

[tex]\\ \rm\longmapsto 18000(0.97)^t[/tex]

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