The properties of cones and cylinders include their base areas, volumes and surface areas.
The question is incomplete; so I will give a general explanation on how base areas, volumes and surface areas can be calculated.
Base Area
Assume the figure is a cone of the following dimension:
Radius (r) = 3 meters
Height (h) = 4 meters
Slant height (l) = 5 meters
The base area is the area of the base.
A cone has a circular base.
So, the base area (b) is:
[tex]b = \pi r^2[/tex]
So, we have:
[tex]b = 3.14 * 3^2[/tex]
[tex]b = 28.26[/tex]
Volume
The volume of a cone is calculated as:
[tex]V = \frac13 \pi r^2h[/tex]
So, we have:
[tex]V = \frac13 * 3.14 * 3^2 * 4[/tex]
[tex]V = 37.68[/tex]
Surface Area
The surface area is calculated as:
[tex]A = \pi r(r+\sqrt{h^2+r^2})[/tex]
So, we have:
[tex]A = 3.14 * 3(3+\sqrt{4^2+3^2})[/tex]
[tex]A = 75.36[/tex]
Using the assumed values, the base area, volume and the surface area of the cone are 28.26, 37.68 and 75.36 respectively.
Read more about three-dimensional figures at:
https://brainly.com/question/6613758