Question

Herman plans to paint a triangular section of his house. The house is 20 feet long. The height of the triangular section is 8 feet. How many square feet of paint will Herman need?

Answer 1

Answer:

Step-by-step explanation:

The question is about area of a triangle

The formula for a triangle's area is

Area = 1/2 h * b

h = 8

b = 20

Solution

Area = 1/2 20 * 8

Area = 80 ft^2

Answer 2

✪ Question -:

Herman plans to paint a triangular section of his house. The house is 20 feet long. The height of the triangular section is 8 feet. How many square feet of paint will Herman need?

✪ Explanation -:

Given -

• Base of the house (b = 20 feet)
• Height of the house (h = 8 feet)

Need to find -

• Square feet of paint Herman need to paint the triangular section of the house

Solution -

This question is based on Area of a triangle to solve this question we need to calculate the area of the triangular section of the house.

We know,

$⍟ \large \ \boxed { \rm{ Area_{(triangle)} = \dfrac{1}{2} × b × h }}$

Where,

• h stand for height
• b stand for base

Substituting the value of h = 8 feet and b = 20 feet

$\large\sf{ Area_{(triangle)} = \dfrac{1}{2} × 20 × 8 }$

$\large\rm{ Area_{(triangle)} = \dfrac{1} { \cancel{2}} × \cancel{20 }× 8 }$

$\large\rm{Area_{(triangle)} = 10 × 8}$

$\large \red{\underline{\color {red} \boxed{ \sf{Area_{(triangle)} = 80 \: {feet}^{2 }} }}}$

Hence, Herman need 80 square feet of paint to paint the triangular section of his house

$\rule{182mm}{4pt}$

Additional Information -

Formulas of Area

• Area of a rectangle = Length × Breadth
• Area of a square = side × side
• Area of a circle = π${r}^{2}$
• Area of a parallelogram = Base × Height