Question

The window shown is the shape of a semicircle with a radius of 6 feet. the distance from f to e is 3 feet and the measure of arc b c = 45°. find the area of the glass in region bcih, rounded to the nearest square foot. ft2

Answer 1

The area of the glass in the region BCIH, rounded to the nearest square foot is 11.

The radius of the semicircle is 6 feet and the distance from F to E is 3 feet. The measure of an arc is 45°.

What is the area of the sector?

First, the sector is the part of the circle made of the arc of the circle along with its radii. The area of the sector of a circle is represented by

The angle of the sector is 360°

The area of the circle $\rm \pi r^{2}$ and the angle is ∅

The area of the sector,  $\rm A= \frac{\Theta}{360} \times\pi r^{2}$

Here, the area of the glass in region BCIHis the difference between the area of the sector of region BCIGH and the region HIG.

The area of the region BCIH

$\rm = \frac{\ 45}{360} \times\pi (6^{2} -3^{2} )$

$\rm = \frac{\ 1}{8} \times\pi (27 )$

$\rm = 10.5\; ft^{2}$

Hence, The area of the glass in the region BCIH, rounded to the nearest square foot is 11.

Learn more about the area of the sector here;

https://brainly.com/question/15849991

Answer 2

Answer:

11 ft2

Step-by-step explanation:

hope this helps