Line jk passes through points j(–3, 11) and k(1, –3). what is the equation of line jk in standard form? 7x 2y = –1 7x 2y = 1 14x 4y = –1 14x 4y = 1

Respuesta :

The equation of the line passing through the points (–3, 11) and (1, –3) is 7x +2y = 1. Then the correct option is B.

What is the linear system?

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

The line JK passes through points J(–3, 11) and K(1, –3).

We know that the equation of a line passing through two points is given as

[tex]\rm (y - y_1) = \dfrac{y_2-y_1}{x_2-x_1} (x - x_1)[/tex]

Then we have

[tex]\rm (y - 11) = \dfrac{-3-11}{1 + 3} (x + 3)\\\\\\(y - 11) = \dfrac{-14}{4} (x +3)\\\\\\(y - 11) = \dfrac{-7}{2}(x +3)\\\\\\2y - 22 \ = -7x -21\\\\\\7x + 2y \ = 1[/tex]

The equation of the line passing through the points (–3, 11) and (1, –3) is 7x +2y = 1. Then the correct option is B.

More about the linear system link is given below.

https://brainly.com/question/20379472

Answer:

its B i took the final and its B

Step-by-step explanation: