Answer:
28
Step-by-step explanation:
Given:
Let [tex]x[/tex] = first number
[tex]\implies \dfrac76x = \textsf{second number}[/tex]
Therefore, as the sum of the two numbers is 52:
[tex]\implies \dfrac76x+x=52[/tex]
[tex]\implies \dfrac76x+\dfrac66x=52[/tex]
[tex]\implies \dfrac{13}{6}x=52[/tex]
[tex]\implies13x=52 \cdot 6[/tex]
[tex]\implies13x=312[/tex]
[tex]\implies x=\dfrac{312}{13}[/tex]
[tex]\implies x=24[/tex]
Therefore, the largest number is:
[tex]\implies \dfrac76\cdot 24 =\dfrac{168}{6}=28[/tex]