Respuesta :

Answer:

28

Step-by-step explanation:

Given:

  • sum of two numbers = 52
  • one number is 7/6 times the second number

Let [tex]x[/tex] = first number

[tex]\implies \dfrac76x = \textsf{second number}[/tex]

Therefore, as the sum of the two numbers is 52:

[tex]\implies \dfrac76x+x=52[/tex]

[tex]\implies \dfrac76x+\dfrac66x=52[/tex]

[tex]\implies \dfrac{13}{6}x=52[/tex]

[tex]\implies13x=52 \cdot 6[/tex]

[tex]\implies13x=312[/tex]

[tex]\implies x=\dfrac{312}{13}[/tex]

[tex]\implies x=24[/tex]

Therefore, the largest number is:

[tex]\implies \dfrac76\cdot 24 =\dfrac{168}{6}=28[/tex]

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