Question

(11^2x × 11^1 - 6 × 121^x )÷ (5 × 121^x)​

Answer 1

Answer:

$\frac{1331x-6\times \:121^x}{5\times \:121^x}$

Step-by-step explanation:

$\frac{11^2x\times \:11^1-6\times \:121^x}{5\times \:121^x}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\times \:a^c=a^{b+c}$

$11^2\times \:11^1=11^{2+1}$

$=\frac{11^{2+1}x-6\times \:121^x}{5\times \:121^x}$

$\mathrm{Add\:the\:numbers:}\:2+1=3$

$=\frac{11^3x-6\times \:121^x}{5\times \:121^x}$

$11^3=1331$

$=\frac{1331x-6\times \:121^x}{5\times \:121^x}$

[RevyBreeze]

Answer 2

Answer:

1

Step-by-step explanation:

$\dfrac{11^{2x} \times 11^1 - 6 \times 121^x}{5 \times 121^x} =$

​$= \dfrac{11 \times 11^{2x} - 6 \times 11^{2x}}{5 \times 11^{2x}}$

​$= \dfrac{5 \times 11^{2x}}{5 \times 11^{2x}}$

​$= 1$