Question

The age of the father is 42 and the age of the son is 9. At what age, will the father be twice old as the son?

(Solve by equation system.)

Answer 1

Answer:

24

Step-by-step explanation:

42 + x = 2 (9 +x) (solve for x)

42 + x = 18 + 2x

42 -18 = 2x -x

24 = x

42 + 24 = 66

9 + 24 = 33

When the man turns 66, his son will be 33, or half his age.