Question

Find the value of x to the nearest tenth.

Answer 1

Answer:

x = 57.8°

explanation:

• opposite length : 11

• hypotenuse length : 13

$\sf sin(x)= \dfrac{opposite}{hypotensue}$

$\hookrightarrow \sf sin(x) = \dfrac{11}{13}$

$\hookrightarrow \sf x = sin^{-1}(\dfrac{11}{13} )$

$\hookrightarrow \sf x = 57.8$

Answer 2

Answer:

57.8° (nearest tenth)

Step-by-step explanation:

Use the sine trig ratio:

$\mathsf{\sin(\theta)=\dfrac{O}{H}}$

where:

• $\theta$ is the angle
• O is the side opposite the angle
• H is the hypotenuse

Given:

• $\mathsf{\theta=x}$
• O = 11
• H = 13

$\implies \mathsf{\sin(x)=\dfrac{11}{13}}$

$\implies \mathsf{x=\arcsin\dfrac{11}{13}}$

$\implies \mathsf{x=57.8 \textdegree \ (nearest \ tenth)}$