Respuesta :
574 grams of NaNO₃ is needed to make 4.50 L of a 1.50 M NaNO₃ solution.
How we calculate mass from moles?
Mass of any substance will be calculated from moles as:
n = W/M, where
W = required mass
M = molar mass
First we calculate the moles of NaNO₃ from molarity as:
n = M × V, where
M = molarity of NaNO₃ = 1.50 M
V= volume of NaNO₃ = 4.50 L
Moles of NaNO₃ = 1.50 × 4.50 = 6.75 moles
Given molar mass of NaNO₃ = 85 g/mole
Now we calculate all these values on the above equation and calculate the required mass of NaNO₃ as:
W = 6.75 × 85 = 573.75 g or 574 grams
Hence, 574 grams is the required mass of NaNO₃.
To know more about moles, visit the below link:
https://brainly.com/question/1464305
