Question

please help me please
$\frac{ {5}^{x + 3 } - 50 \times {5}^{x - 2} }{41 \times {5}^{x} }$
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Answer 1

Answer:

$\frac{ {5}^{x + 3} - 50 \times {5}^{x - 2} }{41 \times {5}^{x} } \\ \\ \frac{ ({5}^{x} \times {5}^{3}) - 50 \times ( {5}^{x} \times {5}^{ - 2} )}{41 \times {5}^{x} }$

Divide the numerator and denominator ÷ 5^x

$\frac{ {5}^{3} - 50 \times {5}^{ - 2} }{41} \\ \\ \frac{ {5}^{3} - 50 \times \frac{1}{ {5}^{2} } }{41 } \\ \\ \\ \frac{ {5}^{3} - \frac{50}{ {5}^{2} } }{41} \\ \\ \\ \frac{ {5}^{3} - \frac{50}{25} }{41} \\ \\ \\ \frac{ {5}^{3} - 2 }{41} \\ \\ \\ \frac{(5 \times 5 \times 5) - 2}{41} \\ \\ \\ \frac{125 - 2}{41} = \frac{123}{41} = 3$