Question

A chemist makes a solution of naoh for use in an experiment. she dissolves 0.00500 mol naoh in 1.00 l h2o. the naoh completely dissociates to form a solution with [oh− ] = 0.00500 m. what is the poh of this solution? 0.00500 5.00 2.30 –2.30

Answer 1

-2.30 is the pOH of the NaOH solution.

How pOH is calculated?

pOH of any solution is define as the negative logarithm of the concentration of OH⁻ ion present in the solution, and it is represented as:

pOH = -log[OH⁻]

In the question it is given that solution is made from NaOH and NaOH is completely dissociate in the solution. So, the concentration of OH⁻ ion is equal to the concentration of NaOH.

Concentration of NaOH will be calculated in the terms of molarity as:

M = n/V, where

n = moles of NaOH = 0.005 mole

V = volume of NaOH = 1 L

M = 0.005/1 = 0.005 M

So, concentration of OH⁻ ion = 0.005 M

Value of pOH will be calculated as:

pOH = -log(0.005) = -2.30.

Hence, option (4) is correct i.e. -2.30.

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Answer 2

Answer:

C

2.30

Explanation:

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