Question

A 1.00 l volume of hcl reacted completely with 2.00 l of 1.50 m ca(oh)2 according to the balanced chemical equation below. 2hcl ca(oh)2 right arrow. cacl2 2h2o what was the molarity of the hcl solution? 0.375 m 1.50 m 3.00 m 6.00 m

Answer 1

6 M is the molarity of the HCl solution with volume 1 liter.

How we calculate molarity?

Molarity (M) of solution is define as the number of moles (n) of solute present in per liter (V) of solution, i.e. M = n/V.

Given chemical reaction is:

2HCl + Ca(OH)₂ → CaCl₂ + 2H₂O

Given volume of HCl = 1 L

Given volume of Ca(OH)₂ = 2 L

Molarity of Ca(OH)₂ = 1.50M

Moles of Ca(OH)₂ = 1.50 × 2 = 3 moles

From the stoichiometry of the reaction:

1 mole of Ca(OH)₂ = react with 2 moles of HCl

3 mole of Ca(OH)₂ = react with 2×3=6 moles of HCl

Molarity of HCl will be calculated by using the above given formula as:

M = 6/1 = 6M.

Hence, option (4) is correct i.e. 6 M.

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Answer 2

Answer:

D

Explanation:

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