Answer :
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Explanation :
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To Find :
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Solution :
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We know,
[tex]{ \longrightarrow\qquad \bf\pi {r}^{2}h = \bf{Volume_{(cylinder) } }}[/tex]
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Where,
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Now, Substituting the values :
[tex]{ \longrightarrow\qquad \sf\pi \times {(2.5)}^{2} \times h = {50 \pi } }[/tex]
[tex]{ \longrightarrow\qquad \sf\pi \times 6.25 \times h = {50 \pi } }[/tex]
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Cancelling π from both sides :
[tex]{ \longrightarrow\qquad \sf \cancel\pi \times 6.25 \times h = {50 \: \cancel \pi } }[/tex]
[tex]{ \longrightarrow\qquad \sf 6.25 \times h = {50 } }[/tex]
[tex]{ \longrightarrow\qquad \sf h = { \dfrac{50}{6.25} } }[/tex]
[tex]{ \longrightarrow\qquad {\pmb {\bf{h = {8 } }}}}[/tex]
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Therefore,