Question

HELP O_O

Use the remainder theorem to find the remainder when p(x)=x^4-9x^3-5x^2-3x+4 is divided by x+5


A.) 1644
B.) 1244
C.) -636
D.) -644

Answer 1

Answer:

A.) 1644

given equation:  $\sf p(x)=x^4-9x^3-5x^2-3x+4$

To be divided with ( x + 5 )

Then,

x + 5 = 0

x = -5

Put this into the equation to find the remainder.

$\sf p(x)=(-5)^4-9(-5)^3-5(-5)^2-3(-5)+4$

$\sf p(x)= 1644$

Answer 2

Use the remainder theorem to find the remainder when p(x)=x^4-9x^3-5x^2-3x+4 is divided by x+5

A.) 1644

B.) 1244

C.) -636

D.) -644

~~~~~~~~~~~~~~~~~~~~~

$\sf p(x)=x^4-9x^3-5x^2-3x+4$

$\sf p(x) = (-5)^4 - 9(-5)^3 (-5)^2 - 3 (-5) + 4$

$\sf \green {(p(x) = 1644)}$

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