Respuesta :
The [tex]x^{th}[/tex] number in the sequence will be [tex]F[x]=\dfrac{5}{2} F[x][/tex]
What will be the xth number in the sequence?
The given function is
[tex]F[x]=\dfrac{3}{2} \times \dfrac{5}{2}^{x-1}[/tex]
Now at [tex]x=x+1[/tex] for the function
[tex]F[x+1]=\dfrac{3}{2} \times \dfrac{5}{2}^{x+1-1}[/tex]
[tex]F[x+1]=\dfrac{3}{2} \times \dfrac{5}{2}^{x }[/tex]
Now we can write
[tex]F[x+1]=\dfrac{3}{2} \times \dfrac{5}{2}^{x-1} \dfrac{5}{2}^1[/tex]
Since [tex]F[x]=\dfrac{3}{2} \times \dfrac{5}{2}^{x-1}[/tex]
so
[tex]F[x]=\dfrac{5}{2} F[x][/tex]
Thus the [tex]x^{th}[/tex] number in the sequence will be [tex]F[x]=\dfrac{5}{2} F[x][/tex]
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