The product of the provided binomial numbers (9 t minus 4)(negative 9 t minus 4) is equal to the option B which is,
[tex]-81t^2+16[/tex]
Product is the resultant number which is obtained by multiplying a number with another. Let a number a is multiplied by number b. Then the Product of these two number will be,
[tex]p=a\times b[/tex]
Here, (a, b) are the real numbers.
The binomial given in the problem are,
[tex](9t-4)\\(-9t-4)[/tex]
Let the product of the above function is p. Thus,
[tex]p=(9t-4)\times(-9t-4)[/tex]
To find the product of these two binomials, multiply the first term of first binomial with both the terms of the second binomial.
Similarly, multiply the second term of first binomial with both the terms of second binomial. Thus,
[tex]p=9t(-9t-4)-4(-9t-4)\\p=-81t^2-36t+36t+16\\p=-81t^2+16[/tex]
Thus, the product of the provided binomial numbers (9 t minus 4)(negative 9 t minus 4) is equal to the option B which is,
[tex]-81t^2+16[/tex]
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