Question

What is the quotient of startfraction negative 8 x superscript 6 baseline over 4 x superscript negative 3 baseline endfraction? startfraction x superscript 9 baseline over 32 endfraction 4x9 negative startfraction 12 over x squared endfraction –2x9

Answer 1

The quotient of the provided fractional number is equal to the option D which is,

$-2x^9$

What is the quotient?

Quotient is the resultant number which is obtain by dividing a number with another. Let a number a is divided by number b. Then the quotient of these two number will be,

$q=\dfrac{a}{b}$

Here, (a, b) are the real numbers.

The fraction given in the problem is,

$\dfrac{-8x^6}{4x^{-3}}$

Let the quotient of the above function is q. Thus,

$q=\dfrac{-8x^6}{4x^{-3}}$

In a fraction number, a negative power of a number in the denominator can be written with a positive number in the numerator and vise versa. Thus,

$q=\dfrac{-8x^6(x^3)}{4}\\q=-2x^{6+3}\\q=-2x^9$

Hence, the quotient of the provided fractional number is equal to the option D which is,

$-2x^9$

Learn more about the quotient here;

https://brainly.com/question/673545

Answer 2

Answer:

It's D -2x^9

Step-by-step explanation: