Question

The magnitude, m, of an earthquake is defined to be m = log startfraction i over s endfraction, where i is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and s is the intensity of a "standard" earthquake, which is barely detectable. what is the magnitude of an earthquake that is 35 times more intense than a standard earthquake? use a calculator. round your answer to the nearest tenth. –1.5 –0.5 1.5 3.6

Answer 1

The magnitude of an earthquake that is 35 times more intense than a standard earthquake is 1.5.

What is the magnitude of an earthquake?

The magnitude of an earthquake is the measured of the amplitude r the size of the seismic waves which is produced by the earthquake.

The magnitude, m, of an earthquake is defined to be

$m = \log\left( \dfrac{I}{S}\right)$

Here (I) is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and (S) is the intensity of a "standard" earthquake, which is barely detectable.

The magnitude of an earthquake that is 35 times more intense than a standard earthquake has to be find out. The Intensity of this earth quack can be given as,

$I=35S$

Put this values in the above formula as,

$m = \log\left( \dfrac{35 S}{S}\right)\\m = \log\left( 35 \right)\\m\approx 1.5$

Thus, the magnitude of an earthquake that is 35 times more intense than a standard earthquake is 1.5.

Learn more about the magnitude of an earthquake here;

https://brainly.com/question/18109453

Answer 2

Answer:

c. or 1.5

Step-by-step explanation: