Respuesta :

The answer is 6
Explanation: because you substitute the given value of x which is 10 into x so 3(10) and multiply that which would give you 30+5x=60 after that subtract 30 from both sides to get 5x alone so 60-30=30 so now we have 5y=30 now divide5 from both sides to get y alone so 5 cancels 5 and 30 divided by 5 would give you y=6

Given :-

  • x = 10
  • 3x + 5y = 60

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To find :-

  • value of y

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Solution :-

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[tex] \looparrowright \sf3x + 5y = 60[/tex]

Put value of x in the equation!

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[tex] \looparrowright \sf3(10)+ 5y = 60[/tex]

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[tex] \looparrowright \sf3 \times 10+ 5y = 60[/tex]

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[tex] \looparrowright \sf30+ 5y = 60[/tex]

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[tex] \looparrowright \sf5(6 + y) = 60[/tex]

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[tex] \looparrowright \sf(6 + y) = 60 \div 5[/tex]

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[tex] \looparrowright \sf6 + y= \dfrac{60}{5} [/tex]

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[tex] \looparrowright \sf6 + y=\cancel \dfrac{60}{5} [/tex]

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[tex] \looparrowright \sf6 + y= \dfrac{12}{1} [/tex]

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[tex] \looparrowright \sf6 + y=12[/tex]

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[tex] \looparrowright \sf y=12 - 6[/tex]

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[tex] \looparrowright \bf y=6[/tex]

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Verification:-

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[tex] \looparrowright \sf3x + 5y = 60[/tex]

Put value of x and y.

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[tex] \looparrowright \sf3(10)+ 5(6) = 60[/tex]

[tex] \\ [/tex]

[tex] \looparrowright \sf3 \times 10+ 5(6) = 60[/tex]

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[tex] \looparrowright \sf30+ 5(6) = 60[/tex]

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[tex] \looparrowright \sf30+ 5 \times 6= 60[/tex]

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[tex] \looparrowright \sf30+ 30= 60[/tex]

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[tex] \looparrowright \bf60= 60[/tex]

LHS = RHS

HENCE VERIFIED!

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