With the earth's atmosphere at approximately 78% nitrogen and 21% oxygen, we have that the mass in grams of oxygen is mathematically given as
Mass of O2=2.74.7g
Question Parameters:
Earth's atmosphere is approximately 78% nitrogen and 21% oxygen.
Generally, the equation for the ideal gas is mathematically given as
PV=nRT
Therefore
n=PV/RT
n=1*1000L/0,0821*298k
n=40.87mol
In conclusion
Where mole of O is 8.58
Therefore
Mass of O2=8.58*32
Mass of O2=2.74.7g
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