Question

Complete the slope-intercept form of the linear equation that represents the
relationship in the table.

Answer 1

Answer:

$\mathsf{y=3x-4}$

Step-by-step explanation:

$\mathsf{point \ slope \ form \ of \ linear \ equation: \ \ y-y_1=m(x-x_1)}$

$\mathsf{slope \ (m)=\dfrac{y_2-y_1}{x_2-x_1}}}$

(where m is the slope and $\mathsf{(x_1,y_1)}$ and $\mathsf{(x_2,y_2)}$ are points on the line)

Given:

• $\mathsf{(x_1,y_1)=(1,-1)}$
• $\mathsf{(x_2,y_2)=(4,8)}$

$\implies \mathsf{slope=\dfrac{8--1}{4-1}}=3}$

Substuting m = 3 and point (1, -1) into the point-slope form of a linear equation:

$\implies \mathsf{y-(-1)=3(x-1)}$

$\implies \mathsf{y=3x-4}$