Given :
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To Find :
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Answer :
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Explanation :
We know that,
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Therefore,
[tex]{ \longrightarrow \sf \qquad \angle1 + \angle2 + \angle3= 180 {}^{ \circ} }[/tex]
[tex]{ \longrightarrow \sf \qquad 50 {}^{ \circ} + 58{}^{ \circ}+\angle3= 180 {}^{ \circ} }[/tex]
[tex]{ \longrightarrow \sf \qquad 108{}^{ \circ}+\angle3= 180 {}^{ \circ} }[/tex]
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Subracting 108° from both sides :
[tex]{ \longrightarrow \sf \qquad 108{}^{ \circ} - 108 {}^{ \circ} +\angle3= 180 {}^{ \circ} - 108 {}^{ \circ} }[/tex]
[tex]{ \longrightarrow \pmb{\bf \qquad \angle3= 72 {}^{ \circ} }}[/tex]
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Therefore,