This question involves the concepts of the speed of sound, frequency, and temperature.
The temperature of the air is "14.24 °C".
First, we find the speed of sound at the given temperature:
v = fλ
where,
Therefore,
v = (695 Hz)(0.49 m)
v = 340.55 m/s
Now, the relationship between the speed of sound and temperature can be given by the following formula:
[tex]\frac{v}{v_o} = \sqrt{\frac{T}{273\ k}}\\\\T = (273\ k)(\frac{v}{v_o})^2\\\\[/tex]
where,
Therefore,
[tex]T = (273\ k)(\frac{340.55\ m/s}{332\ m/s})^2[/tex]
T = 287.24 k = (278.24 k -273) °C
T = 14.24 °C
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