Answer and step by step esplanation:
The perpendicular line has the slope opposite and inverse, in our case [tex]-4 \rightarrow +\frac14[/tex]
Line passing through the point will have then equation - using the point-slope form [tex]y-y_0=m(x-x_0)[/tex]
[tex]y-5=\frac14 (x-(-5))\\y-5=\frac14(x+5)[/tex]
The parallel line will have the same slope as the given line, in our case -4. Again with the point-slope equation:
[tex]y-5=-4(x-(-5)\\y-5=-4(x+5)[/tex]