Question

A line has a slope of 110 and passes through the point (5,10). What is its equation in point-slope form? Use the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions

Answer 1

Answer:

y - 10 = 110 ( x - 5)

explanation :

i)

$\sf point \ slope \ form : \bold{y-y_{1}=m\left(x-x_{1}\right)}$

• y - 10 = 110 ( x - 5)

ii)

• y = 110x -540

• 10 = 110(5) - 540

• 10 = 550 - 540

• 10 = 10

Answer 2

Answer:

$y=110x-540$

Step-by-step explanation:

Point-slope form of a linear equation:  $y-y_1=m(x-x_1)$

(where $m$ is the slope and $(x_1,y_1)$ is a point on the line)

Given:

• $\textsf{slope } (m) = 110$
• $(x_1,y_1)=(5,10)$

Substitute these values into the equation:

$y-y_1=m(x-x_1)$

$y-10=110(x-5)$

$y-10=110x-550$

$y=110x-540$