Question

please help me solve x^2-2x-1=x+3

Answer 1

Answer:

x = -1 or x = 4

Step-by-step explanation:

$x^2-2x-1=x+3$

subtract $x$ from both sides:

$\implies x^2-2x-1-x=x+3-x$

$\implies x^2-3x-1=3$

subtract 3 from both sides:

$\implies x^2-3x-1-3=3-3$

$\implies x^2-3x-4=0$

factor:

$\implies x^2+x-4x-4=0$

$\implies x(x+1)-4(x+1)=0$

$\implies (x-4)(x+1)=0$

Therefore,

$x-4=0 \implies x=4$

$x+1=0 \implies x=-1$