This problem is providing us with the mass of an unknown element which produces 43.5 g of M3N2. Thus, its name and molar mass are required and found to be 4.02 g/mol and calcium nitride after the following:
Stoichiometry.
In chemistry, stoichiometry is a tool used for the calculation of masses or moles involved in chemical reactions, by the utilization of molar masses and mole ratios based on proportional factors.
In such a way, for the given reaction, one can use the formulas to write the following balanced chemical equation:
[tex]3M+N_2\rightarrow M_3N_2[/tex]
Where there is a 3:1 mole ratio of the metal to the product, which means we can use the following stoichiometric setup:
[tex]35.3gM*\frac{1molM}{x}*\frac{1molM_3N_2}{3molM} *\frac{(3x+14.01*2)gM_3N_2}{1molM_3N_2}=43.5gM_3N_2[/tex]
Now, by using the numbers only, one will be able to calculate x as the atomic mass of the element M in g/mol:
[tex]35.3*\frac{1}{x}*\frac{1}{3} *\frac{3x+14.01*2}{1}=43.5\\\\\frac{105.9x+989.106}{3x}=43.5\\ \\105.9x+989.106=130.5x\\\\989.106=130.5x-105.9x\\\\x=\frac{989.106}{130.5-105.9} =40.2g/mol[/tex]
Which matches with the molar mass of calcium. Moreover, we find its name as calcium nitride.
Learn more about stoichiometry: brainly.com/question/9743981
