Question

BRAINLIST+DONT SCAM ME
The number of marbles of different colors stored in a hat is listed below:


1 red marble

8 green marbles

9 blue marbles

Without looking in the hat, Ray takes out a marble at random. He replaces the marble and then takes out another marble from the hat. What is the probability that Ray takes out a blue marble in both draws?

fraction 1 over 9

fraction 1 over 8

fraction 1 over 4

fraction 1 over 2

Answer 1

Answer:

1/4

Step-by-step explanation:

1 red marble, 8 green marbles. 9 blue marbles

There are 1+8+9 = 18 marbles

First marble blue

P(blue) = blue / total = 9/18 = 1/2

He replaces the marble so there are still 18 marbles

1 red marble, 8 green marbles. 9 blue marbles

There are 1+8+9 = 18 marbles

Second marble blue

P(blue) = blue / total = 9/18 = 1/2

Multiply the probabilities together

P(blue, replace, blue) = 1/2 * 1/2 = 1/4

Answer 2

• Sorry Im a little late The correct answer is Infact C. Fraction 1 over 4 (Looks like this $\frac{1}{4\\}$)
• I Indeed took the test On FLVS. 8.13  segment exam pt.2. Proof.

Step-by-step explanation:

Have a great Day!