Question :-
- The Area of Parallelogram is 32 cm², its Base is 8 cm . Then find its Height .
Answer :-
- Height of Parallelogram is 4 cm .
[tex] \rule {210pt} {2pt} [/tex]
Given :-
- Area of Parallelogram = 32 cm²
- Base of Parallelogram = 8 cm
To Find :-
- Height of Parallelogram = ?
Solution :-
As per the provided information in the given question, we have been given that the Area of Parallelogram is 32 cm² . Base of Parallelogram is given 8 cm . And, we have been asked to calculate the Height of Parallelogram .
For calculating the Height , we will use the Formula :-
[tex] \bigstar \: \: \boxed{ \sf{ \: Area \: _{Parallelogram} \: = \: Base \: \times \: Height \: }} [/tex]
Therefore , by Substituting the given values in the above Formula :-
[tex] \longmapsto \: \: \sf{ Area \: _{Parallelogram} \: = \: Base \: \times \: Height} \\ [/tex]
[tex] \longmapsto \: \: \sf{ 32 \: = \: 8 \: \times \: Height} \\ [/tex]
[tex] \longmapsto \: \: \sf{ \dfrac{32}{8} \: = \: Height } \\ [/tex]
[tex] \longmapsto \: \: \sf{ \dfrac{4}{1} \: = \: Height } \\ [/tex]
[tex] \longmapsto \: \: \textbf {\textsf {Height = 4 cm}} [/tex]
Hence :-
- Height of Parallelogram = 4 cm .
[tex] \underline {\rule {210pt} {4pt}} [/tex]
Additional Information :-
[tex] \begin{gathered} \begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered} \end{gathered} [/tex]
