Question

i once met six siblings whose ages are 6 consecutive whole numbers. i asked each of them the question how old is your oldest sibling. which of the following could not be the sum of their answers.
A. 95
B. 125
C. 167
D. 205
E. 233

Answer 1

The consecutive ages of the siblings mean that each sibling is a year older than the younger sibling

All the options cannot be the sum of their ages

How to determine the sum of their ages

Represent the age of the smallest sibling with x.

So, the sum of their ages is:

$Sum =x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5$

Evaluate the like terms

$Sum =6x + 15$

When the sum is 95 (from the options), we have:

$6x + 15 = 95$

Subtract 15 from both sides

$6x = 80$

Divide by 6

$x = 13.3$ -- this is not an integer

When the sum is 95 (from the options), we have:

$6x + 15 = 125$

Subtract 15 from both sides

$6x = 110$

Divide by 6

$x = 6.875$ -- this is not an integer

When the sum is 167 (from the options), we have:

$6x + 15 = 167$

Subtract 15 from both sides

$6x = 152$

Divide by 6

$x = 25.33$ -- this is not an integer

When the sum is 205 (from the options), we have:

$6x + 15 = 205$

Subtract 15 from both sides

$6x = 190$

Divide by 6

$x = 31.67$ -- this is not an integer

When the sum is 233 (from the options), we have:

$6x + 15 = 233$

Subtract 15 from both sides

$6x = 218$

Divide by 6

$x = 36.33$ -- this is not an integer

Hence, all the options cannot be the sum of their ages

Read more about consecutive numbers at:

https://brainly.com/question/10853762