Solve these 2 Question. 50 Points + Brainelist
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using simultaneous equation:
2x + 3y = 190
3x + y = 180 * 3
Then:
2x + 3y = 190
9x + 3y = 540
--------------------
-7x = -350
x = 50
Insert this in equation 1 to find value of y:
2x + 3y = 190
2(50) + 3y = 190
3y = 190 - 100
3y = 90
y = 30
expanding the following:
→ (x + 2)³
[tex]\sf apply \ cubic \ formula : \bold{\left(a+b\right)^3=a^3+3a^2b+3ab^2+b^3}[/tex]
[tex]\rightarrow \sf x^3+3x^2\cdot \:2+3x\cdot \:2^2+2^3[/tex]
[tex]\rightarrow \sf x^3+6x^2+12x+8[/tex]
Justify for x = 5
[tex]\rightarrow \sf (5)^3+6(5)^2+12(5)+8[/tex]
[tex]\rightarrow \sf 125+150+60+8[/tex]
[tex]\rightarrow \sf 343[/tex]
Answer:
Step-by-step explanation for (a):
First use system of equations. Isolate a variable and substitute.
2x + 3y = 190
3x + y = 180
Isolate
subtract 3x from both sides of the second equation
y = 180 - 3x
since 180 - 3x = y, you can substitute this into the first equation for y
Substitute
2x + 3y = 190
2x + 3(180 - 3x) = 190
Distribute the 3
2x + (540 - 9x) = 190
Solve for x
subtract 540 from both sides
2x - 9x = -350
simplify
-7x = -350
divide each side by -7
x = 50
But you still need to solve for y, so substitute the x back into the first equation.(But really you could use either equation)
2(50) + 3y = 190
subtract 100 (2 * 50) from both sides
3y = 90
y = 30
Check your work by resubstituting.
3(50) + 30 = 180.
(b) This one is weird.
(Remember, it is NOT (x^3 + 8), you don't "distribute" the exponent)
It then simplifies to x^3 + 6x^2 + 12x + 8, and x = 5 is NOT an answer here. Maybe there is something more that you might not have screenshotted?
*edit its not asking to prove x is a solution(which i thought lolllll) its asking to plug x = 5 into the equation*