Question

A body starts from rest and travels with uniform acceleration of 2 m/s², if its velocity is v after making a displacement of 9 m . Then find the value of v .​

Answer 1

Question :-

• A body starts from Rest and travels with Uniform Acceleration of 2 m/s². If its Velocity is v after making a Displacement of 9 m . Then find the value of 'v' .

Answer :-

• The value of Final Velocity is 6 m/s .

$\rule {180pt} {2pt}$

Given :-

• Initial Velocity = 0 m/s
• Acceleration = 2 m/s²
• Displacement = 9 m

To Find :-

• Final Velocity = ?

Solution :-

As per the provided information in the given question, Initial Velocity is given 0 m/s . Acceleration is given 2 m/s² . Displacement is given 9 m . And, we have been asked to calculate the Final Velocity .

For calculating the Final Velocity , we will use 3ʳᵈ Equation of Motion :-

• $\sf {ᴠ ^{2} \: - \: ᴜ ^{2} \: = \: 2 \: ᴀs}$

Where ,

• ᴠ² denotes to the Final Velocity
• ᴜ² denotes to the Initial Velocity
• ᴀ denotes to the Acceleration
• s denotes to the Displacement

Therefore , by Substituting the given values in the above Equation :-

$\longmapsto \: \: \sf {ᴠ ^{2} \: - \: ᴜ ^{2} \: = \: 2 \: \times \: ᴀ \: \times \: s}$

$\longmapsto \: \: \sf {ᴠ ^{2} \: - \: 0 \: = \: 2 \: \times \: 2 \: \times \: 9}$

$\longmapsto \: \: \sf {ᴠ ^{2} \: - \: 0 \: = \: 36}$

$\longmapsto \: \: \sf {ᴠ ^{2} \: = \: 36}$

$\longmapsto \: \: \sf {ᴠ \: = \: \sqrt { \: 36 \: }}$

$\longmapsto \: \: \textbf {\textsf {ᴠ \: = \: 6}}$

Hence :-

• Final Velocity = 6 m/s .

$\underline {\rule {180pt} {4pt}}$