The molar mass of the element M is mathematically given as
M=91.927g/mol
Question Parameters:
A 35.3 g of element M is reacted with nitrogen to produce 43.5 g of compound M3N2.
Generally, the equation for the Chemical Reaction is mathematically given as
3M+N2=M3N2
Therefore
moles of N2 is given as
[tex]m=\frac{mass of N2}{molar mass}[/tex]
Where
mass of N2=43.5-35.3
mass of N2=8.2
Therefore
[tex]m=\frac{8.2}{32}[/tex]
m=0.25625mole
Since 2 moles of N2 reacts with 3mols of M
Hence, 0.25625 mole of N2 reacts with 3mole of M
x=3/2*0.256
x=0.384mol
In conclusion, the molar mass of M
[tex]M=\frac{mass of x}{moles of x}\\\\M=\frac{35.3}{0.384}[/tex]
M=91.927g/mol
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