Question

For what value of p are 2p + 1, 13, 5p – 3, three consecutive terms of AP?​

Answer 1

Answer:

4

Step-by-step explanation:

The arithmetic progression terms, are

(2p+1), 13, (5p-3).

First find the distance between 2p+1 and 13.

$13 -( 2p + 1 )= - 2p + 12$

Then find distance between 13, and 5p-3

$5p - 3 - ( 13) = 5p - 16$

Terms in a AP progression should have same distances as each other.

$5p - 16 = - 2p + 12$

$7p = 28$

$p = 4$

Answer 2

Answer:

Given 2p+1, 13 , 5p-3 are in AP. P is 4.