Question

Ajar contains 35 dimes and nickels. The total value of the coins is $2.50. If
d = the number of dimes and n = the number of nickels, this is the system of
equations:
d+ n = 35
0.100+ 0.05n = 2.50
How many of each type of coin are there? Solve the system to answer the
question

Answer 1

Answer:

0.05x+0.10(35-x)=2.50

(0.05x+3.5-0.10x=2.50) get rid of devimal points by multiplying both sides by 100

• 5x+350-10x=250
• 5x-10x +350-350=250-350
• (-5x= 100)divide both by -5
• -5x/-5= -100/-5
• x=20(the number of nickels)

• The number of dime is
• 35-x. and x=20
• 35-20=15
• the number of dimes is = 15
• the number of nickels is = 20
• 20nickels =$1.00
• 15dimes =$1.50

check

• the number of dimes + the number of nickels is $2.50
• d+n=$2.50. : d=$1.50 and n=$1.00
• $1.50 + 1.00 =$2.50