A triangle has a base of 8 feet and a height of 6 feet. By how much does the height need to increase for the area to increase by 2 square feet? Write your answer as a decimal. plss help me

Respuesta :

Answer:

0.5 ft

Step-by-step explanation:

Base = 8 ft and Height = 6 ft

Area of Triangle = 0.5*b*h

Area of Triangle = 0.5*8*6 = 24 sq.ft

To increase the Area by 2 sq.ft  so the New Area will be 26 sq.ft

New Area = 0.5*b*(New Height)

26=0.5*8*(New Height)

New Height = 6.5 ft

The Increase in Height = New Height - Old Height =  6.5 - 6 = 0.5 ft

The increase in the height of the triangle which has a base of 8 feet and a height of 6 feet, to increase its area by 2 square feet is 0.5 feet.

How do we determine the area of a triangle?

The area of a triangle is half the product of its base and its height, that is,

Area = (1/2)*base*height.

How do we solve the given question?

We have been asked to find the increase in the height of a triangle with base(b) = 8 feet and height(h) = 6 feet, such that its area increases by 2 square feet.

First, we find the initial area of the triangle,

Area = (1/2)*b*h (1/2)*8*6 = 24 square feet.

New area = initial area + 2 square feet = 24 + 2 = 26 square feet

Let the increase in height be x feet,

∴ New height(h1) = 6+x feet

∴ New area = (1/2)*8*(6+x),

But we know that the new area is 26 square feet, so we equate them to get:

(1/2)*8*(6+x) = 26

or, 4(6+x) = 26

or, 24 + 4x = 26

or, 4x = 26 - 24 = 2

or, x = 2/4 = 0.5

∴ The increase in the height of the triangle which has a base of 8 feet and a height of 6 feet, to increase its area by 2 square feet is 0.5 feet.

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