Question

A cube of Iron, 0.0800 m on a side, has a density of 7874 kg/m^3. What is its mass? a (Unit = kg) ​

Answer 1

The mass of the iron cube of side 0.0800 m, having a density of 7874 kg/m³ is 50.39 kg.

What is mass?

Mass can be defined as the quantity of matter a body contains

To calculate the mass of the iron cube, we use the formula below.

Formula:

• m = DL³........... Equation 1

Where:

• m = mass of the iron cube
• D = Density of the iron cube
• L = Length of each side of the cube

From the question,

Given:

• D = 7874 kg/m³
• L = 0.08 m

Substitute these values into equation 1

• m = 7874(0.08³)
• m = 50.39 kg

Hence, The mass of the iron cube is 50.39 kg.

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Answer 2

Answer:

4.03

Explanation:

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